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-5n^2=-220
We move all terms to the left:
-5n^2-(-220)=0
We add all the numbers together, and all the variables
-5n^2+220=0
a = -5; b = 0; c = +220;
Δ = b2-4ac
Δ = 02-4·(-5)·220
Δ = 4400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4400}=\sqrt{400*11}=\sqrt{400}*\sqrt{11}=20\sqrt{11}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{11}}{2*-5}=\frac{0-20\sqrt{11}}{-10} =-\frac{20\sqrt{11}}{-10} =-\frac{2\sqrt{11}}{-1} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{11}}{2*-5}=\frac{0+20\sqrt{11}}{-10} =\frac{20\sqrt{11}}{-10} =\frac{2\sqrt{11}}{-1} $
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